Shortcut tricks on principle or sum based are one of the most important topics in exams. Competitive exams are all about time. If you manage your time then you can do well in those exams. Most of us skip that part. Few examples on principle or sum based shortcuts is given in this page below. We try to provide all types of shortcut tricks on principle or sum based here. We request all visitors to read all examples carefully. You can understand shortcut tricks on Principle or Sum based by these examples.
First of all do a practice set on math of any exam. Choose any twenty math problems and write it down on a page. Solve first ten math problems according to basic math formula. You also need to keep track of the time. After finish write down total time taken by you to solve those ten maths. Now practice our shortcut tricks on principle or sum based and read examples carefully. After doing this go back to the remaining ten questions and solve those using shortcut methods. Again keep track of the time. You will surely see the improvement in your timing this time. But this is not enough. You need to practice more to improve your timing more.
Example 1:
Suresh take a sum of money at simple interest amounts to Rs.985 in 2 years and to Rs. 885 in 3 years , find The sum of money suresh was taken.
Answer :
Step 1: Simple interest in 1 year is = Rs.( 985 – 885 ) = 100.
Step 2: Simple Interest in 2 years = Rs.100 X 2 = 200.
Step 3: So,Principal = ( 985 – 200 ) = 785.
Example 2:
Samar take a sum from Anup at simple interest at 25x / 2 per annul and amounts to Rs, 3202.50 after 6 years. Find the Sum or Principal taken by Samar from Anup .
Answer :
First We consider sum is x and Rate percent is 25x / 2 and Time is 6 years, So
Step 1: Then S.I. = P X R X T / 100 = 3x / 4.
Step 2: Amount = Sum + Simple Interest = x + 3x / 4 = 7x / 4.
Step 3: 7x / 4 = 3202.50 and x = 3202.50 X 4 / 7 = 1830.
Samar taken sum from Anup is 1830.
Example 3:
What is the amount of Rs.16000 at 5% per annul compound interest in 3 years ?
Answer :
Time = 3
rate = 5%
16000 x ( 105 / 100 ) = 16000 x 1157625 / 1000000
= 18522
So the amount is 18522.
Example 4:
John borrowed some money at the rate of 4% p.a for the First 3 years. at rate of 7% p.a. for the next 4 years. If he pays a total interest of Rs. 12,600 at the end of seven years, how much money did he borrow ?
Answer :
Let sum borrowed x then P = x
( P X R X T / 100 )
( x X 4 X 3 / 100) + ( x X 7 X 4 / 100) = 12600
( 3x / 25 + 7x / 25 ) = 12600
10x / 25 = 12600
x = 12600 x 25 / 10
x = 31500
So, sum he borrowed = Rs. 31500.
First of all do a practice set on math of any exam. Choose any twenty math problems and write it down on a page. Solve first ten math problems according to basic math formula. You also need to keep track of the time. After finish write down total time taken by you to solve those ten maths. Now practice our shortcut tricks on principle or sum based and read examples carefully. After doing this go back to the remaining ten questions and solve those using shortcut methods. Again keep track of the time. You will surely see the improvement in your timing this time. But this is not enough. You need to practice more to improve your timing more.
Example 1:
Suresh take a sum of money at simple interest amounts to Rs.985 in 2 years and to Rs. 885 in 3 years , find The sum of money suresh was taken.
Answer :
Step 1: Simple interest in 1 year is = Rs.( 985 – 885 ) = 100.
Step 2: Simple Interest in 2 years = Rs.100 X 2 = 200.
Step 3: So,Principal = ( 985 – 200 ) = 785.
Example 2:
Samar take a sum from Anup at simple interest at 25x / 2 per annul and amounts to Rs, 3202.50 after 6 years. Find the Sum or Principal taken by Samar from Anup .
Answer :
First We consider sum is x and Rate percent is 25x / 2 and Time is 6 years, So
Step 1: Then S.I. = P X R X T / 100 = 3x / 4.
Step 2: Amount = Sum + Simple Interest = x + 3x / 4 = 7x / 4.
Step 3: 7x / 4 = 3202.50 and x = 3202.50 X 4 / 7 = 1830.
Samar taken sum from Anup is 1830.
Example 3:
What is the amount of Rs.16000 at 5% per annul compound interest in 3 years ?
Answer :
Time = 3
rate = 5%
16000 x ( 105 / 100 ) = 16000 x 1157625 / 1000000
= 18522
So the amount is 18522.
Example 4:
John borrowed some money at the rate of 4% p.a for the First 3 years. at rate of 7% p.a. for the next 4 years. If he pays a total interest of Rs. 12,600 at the end of seven years, how much money did he borrow ?
Answer :
Let sum borrowed x then P = x
( P X R X T / 100 )
( x X 4 X 3 / 100) + ( x X 7 X 4 / 100) = 12600
( 3x / 25 + 7x / 25 ) = 12600
10x / 25 = 12600
x = 12600 x 25 / 10
x = 31500
So, sum he borrowed = Rs. 31500.
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